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>
>int main(int argc , char *argv[]){
> if(argc != 1){
> fprintf(stderr , "Error 1\");
> return 1;
>}
>
>cp $argv[0] $argv[1]
>
>ImageCopy ¶ó´Â½©À» ÀÌ·¸°Ô Çؼ ®´Âµ¥¿©.ÀÌ°Ô ½ÇÇàÀÌ ¾ÈµË´Ï´Ù.
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>
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>
>./ImageCopy: line 3: syntax error near unexpected token `main(i'
>./ImageCopy: line 3: `int main(int argc , char *argv[]){'
>
>ÀÚ²Ù ÀÌ·±¿¡·¯°¡ ³ª¿À´Âµ¥ ¾Ï¸¸ ã¾ÆºÁµµ ¹«½¼¿¡·¯ÀÎÁö ³ª¿ÍÀÖÁú ¾Ê³×¿ä
>
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========================================
fprintf(stderr , "Error 1\");
°¡ ¾Æ´Ï¶ó
fprintf(stderr , "Error 1\n");
ÀÌ·¸°Ô ÇØ¾ß ÇÕ´Ï´Ù.
C Àü¹®°¡°¡ ¾Æ´Ï¶ó¼...
-- imagecopy.c ------------------------
#include
#include
int main(int argc, char *argv[])
{
FILE *fin, *fout;
char fto[256];
if(argc != 3) { /*** argv[0] Àº ÇÁ·Î±×·¥ ÀڽŠ***/
printf("Error arguments : %d\n", argc-1);
exit(1);
}
if((fin=fopen(argv[1],"r")) == NULL) {
printf("%s file can't read\n", argv[1]);
exit(1);
}
if((fout=fopen(argv[2],"w")) == NULL) {
printf("%s file can't write\n", argv[2]);
exit(1);
}
printf("cp %s %s\n", argv[1], argv[2]);
while(fgets(fto,256,fin) != NULL) {
fputs(fto, fout);
}
fclose(fin);
fclose(fout);
return 0;
}
------------------------------
$ gcc -o imagecopy imagecopy.c
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